Rozwiązanie
[tex]\frac{3a+5a^2}{a}=\frac{a(3+5a)}{a}=\boxed{3+5a}\\\\\frac{5ab+2a^2}{a}=\frac{a(5b+2a)}{a}=\boxed{5b+2a}\\\\\frac{8ab+a(b+3a)}{3a}=\frac{8ab+ab+3a^2}{3a}=\frac{9ab+3a^2}{3a}=\frac{3a(3b+a)}{2a}=\boxed{3b+a}[/tex]
