Cześć ;-)
Obliczenia
[tex]\sqrt8=\sqrt{4\cdot2}=\sqrt{2^2\cdot2}=2\sqrt2\\\\\sqrt{75}=\sqrt{25\cdot3}=\sqrt{5^2\cdot3}=5\sqrt3\\\\\sqrt{72}=\sqrt{36\cdot2}=\sqrt{6^2\cdot2}=6\sqrt2\\\\\sqrt[3]{24}=\sqrt[3]{8\cdot3}=\sqrt[3]{2^3\cdot3}=2\sqrt[3]3\\\\\sqrt[3]{-128}=\sqrt[3]{-64\cdot2}=\sqrt[3]{(-4)^3\cdot2}=-4\sqrt[3]2[/tex]
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