[tex](x^3+8)(x^2+25)(x^2-7)(x^2-16)=0\\x^3=-8~~\vee~~x^2=-25~~\vee~~x^2=7~~\vee~~x^2=16\\x=-2~~\vee~~x\in\oslash~~\vee~~x=-\sqrt{7} ~~\vee~~x=\sqrt{7}~~\vee~~x=-4~~\vee~~x=4[/tex]
Zatem suma rozwiązań owego równania wynosi: [tex]-2-\sqrt{7} +\sqrt{7} +4-4=-2[/tex]
Pozdrawiam.
