Wykorzystamy schemat Hornera
[tex]W(x)=a_3x^3+a_2x^2+a_1x+a_0\\Q(x)=x-b\\W(x):Q(x)=O(x)+reszta\\O(x)=c_2x^2+c_1x+c_0\\\\x^3~~~~~~~~~~~~x^2~~~~~~~~~~~~x^1~~~~~~~~~~~~x^0\\\underline{a_3~~~~~~~~~~~~a_2~~~~~~~~~~~~a_1~~~~~~~~~~~~a_0}\\x^2~~~~~~~~~~~~x^1~~~~~~~~~~~~x^0~~~~~~~~~~~~r.\\a_3~~~~~~b\cdot c_3+a_2~~~~b\cdot c_2+a_1~~~~b\cdot c_1+a_0 \\c_3~~~~~~~~~~~~c_2~~~~~~~~~~~~c_1[/tex]
[tex]W(x)=2x^3-4x^2-15x-12\\P(x)=x+3~~~~b=-3\\W(x):Q(x)=O(x)+reszta[/tex]
[tex]x^3~~~~~~x^2~~~~~~x^1~~~~~~x^0\\\underline{2~~~~-4~~~~-15~~~~-12}\\x^2~~~~~~x^1~~~~~~x^0~~~~~~r.\\2~~~~-10~~~~15~~~~-57\\\\(-3)\cdot2+(-4)=-10\\(-3)\cdot(-10)+(-15)=15\\(-3)\cdot15+(-12)=-57[/tex]
Odp. Wychodzi nam -57 reszty.
