Odpowiedź:
[tex]a)\ \ 3\cdot\dfrac{3}{8}=\dfrac{3\cdot3}{8}=\dfrac{9}{8}=1\dfrac{1}{8}\\\\\\b)\ \ \dfrac{3}{5}\cdot\dfrac{4}{7}=\dfrac{12}{35}\\\\\\c)\ \ \dfrac{5}{\not16_{2}}\cdot\not24^3=\dfrac{5}{2}\cdot3=\dfrac{5\cdot3}{2}=\dfrac{15}{2}=7\dfrac{1}{2}\\\\\\d)\ \ 2\dfrac{2}{9}\cdot\dfrac{3}{5}=\dfrac{\not20^4}{\not9_{3}}\cdot\dfrac{\not3^1}{\not5_{1}}=\dfrac{4}{3}=1\dfrac{1}{3}\\\\\\e)\ \ 3\dfrac{1}{2}\cdot2\dfrac{4}{7}=\dfrac{\not7^1}{\not2_{1}}\cdot\dfrac{\not18^9}{\not7_{1}}=9[/tex]
[tex]f)\ \ 4\dfrac{4}{5}\cdot3\dfrac{3}{4}=\dfrac{\not24^6}{\not5_{1}}\cdot\dfrac{\not15^3}{\not4_{1}}=6\cdot3=18\\\\\\g)\ \ \dfrac{4}{9}:8=\dfrac{\not4^1}{9}\cdot\dfrac{1}{\not8_{2}}=\dfrac{1}{18}\\\\\\h)\ \ 6:\dfrac{2}{3}=\not6^3\cdot\dfrac{3}{\not2_{1}}=3\cdot3=9\\\\\\i)\ \ 1\dfrac{1}{8}:3=\dfrac{\not9^3}{8}\cdot\dfrac{1}{\not3_{1}}=\dfrac{3}{8}[/tex]
[tex]j)\ \ 8\dfrac{1}{3}:\dfrac{5}{6}=\dfrac{\not25^5}{\not3_{1}}\cdot\dfrac{\not6^2}{\not5_{1}}=5\cdot2=10\\\\\\k)\ \ 4\dfrac{1}{5}:2\dfrac{1}{3}=\dfrac{21}{5}:\dfrac{7}{3}=\dfrac{\not21^3}{5}\cdot\dfrac{3}{\not7_{1}}=\dfrac{9}{5}=1\dfrac{4}{5}\\\\\\l)\ \ 1\dfrac{3}{8}:6\dfrac{3}{5}=\dfrac{11}{8}:\dfrac{33}{5}=\dfrac{\not11^1}{8}\cdot\dfrac{5}{\not33_{3}}=\dfrac{5}{24}[/tex]
