Cześć ;-)
Obliczenia
[tex]\frac{4}{5}\cdot1\frac{7}{8}+2\frac{1}{2}:(\frac{1}{3}-\frac{1}{4})=\frac{\not4^1}{\not5_1}\cdot\frac{\not15^3}{\not8_2}+\frac{5}{2}:(\frac{4}{12}-\frac{3}{12})=\\\\=\frac{3}{2}+\frac{5}{2}:\frac{1}{12}=1\frac{1}{2}+\frac{5}{2}\cdot12=1\frac{1}{2}+5\cdot6=\\\\=1\frac{1}{2}+30=31\frac{1}{2}[/tex]
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