[tex]a) \ 32^{2}\cdot27 = (2^{5})^{2}\cdot3^{3}= 2^{10}\cdot2^{3}=2^{7}\cdot2^{3}\cdot3^{3} = 2^{7}\cdot(2\cdot3)^{3} = 2^{7}\cdot6^{3}\\\\\\b) \ 125\cdot25 = 5^{3}\cdot5^{2} = 5^{5}[/tex]
Wyjaśnienie:
[tex]a^{m}\cdot a^{n} = a^{m+n}\\\\(a^{m})^{n} = a^{m\cdot n}[/tex]
