MCuO=80g/mol
d=6,45 g/cm³
[tex]\large{\boxed{V_{M}=\frac{M}{d}}}[/tex]
[tex]\large{V_{M}=\frac{80\frac{g}{mol}}{6,45\frac{g}{cm^{3}}}} = \frac{80}{6,45} \frac{g \cdot cm^{3}}{g \cdot mol}[/tex]
[tex]\large{\boxed{V_{M}=12,4 \frac{cm^{3}}{mol}}}[/tex]
