Zadanie 1
a) [tex]\sqrt{225} =15[/tex] [tex]\sqrt{144}=12[/tex] [tex]\sqrt{10000}=100[/tex]
b) [tex]\sqrt{1\frac{7}{9}} =\sqrt{\frac{16}{9}}=\frac{4}{3}=1\frac{1}{3}[/tex] [tex]\sqrt{2\frac{14}{25}}=\sqrt{\frac{64}{25}}=\frac{8}{5}=1\frac{3}{5}[/tex] [tex]\sqrt{1\frac{48}{121}}=\sqrt{\frac{169}{121}}=\frac{13}{11}=1\frac{2}{11}[/tex]
c) [tex]\sqrt{\frac{3}{48}}=\sqrt\frac{1}{16}}=\frac{1}{4}[/tex] [tex]\sqrt{\frac{8}{50}}=\sqrt\frac{16}{100}}=\frac{4}{10}=\frac{2}{5}[/tex] [tex]\sqrt\frac{20}{45}}=\sqrt\frac{4}{9}}=\frac{2}{3}[/tex]
d) [tex]\sqrt{0,0004}=\sqrt\frac{1}{2500}}=\frac{1}{50}[/tex] [tex]\sqrt{1,69}=\sqrt\frac{169}{100}= \frac{13}{10}=1\frac{3}{10}[/tex] [tex]\sqrt{1,21}=\sqrt\frac{121}{100}}=\frac{11}{10}=1\frac{1}{10}[/tex]
Zadanie 2
a) [tex]\sqrt[3]{125}=5[/tex] [tex]\sqrt[3]{64000}=40[/tex] [tex]\sqrt[3]{-125}=-5[/tex]
b) [tex]\sqrt[3]{-3\frac{3}{8}}=\sqrt[3]{-\frac{27}{8}}=-\frac{3}{2}=-1\frac{1}{2}[/tex] [tex]\sqrt[3]{\frac{1}{64}}=\frac{1}{4}[/tex] [tex]\sqrt[3]{2\frac{10}{27}}=\sqrt[3]{\frac{64}{27}}=\frac{4}{3}=1\frac{1}{3}[/tex]
c) [tex]\sqrt[3]{0,027}=\sqrt[3]{\frac{27}{1000}}=\frac{3}{10}[/tex] [tex]\sqrt[3]{-0,008}=\sqrt[3]{-\frac{8}{1000}}=-\frac{2}{10}=-\frac{1}{5}[/tex] [tex]-\sqrt[3]{-0,064}=-\sqrt[3]{-\frac{64}{1000}}=-(-\frac{4}{10})=\frac{4}{10}[/tex]
Liczę, że pomogłam ; )
