[tex]dane:\\p = 20 \ hPa = 2 \ 000 \ Pa = 2 \ 000 \ \frac{N}{m^{2}}\\F = 8 \ N\\szukane:\\S = ?\\\\Rozwiazanie\\\\p = \frac{F}{S} \ \ /\cdot S\\\\p\cdot S = F \ \ /:p\\\\S = \frac{F}{p}\\\\S = \frac{8 \ N}{2000 \ Pa} = \frac{8 \ N}{2000\frac{N}{m^{2}}}\\\\S = 0,004 \ m^{2}=40 \ cm^{2}[/tex]
