Proszę o obliczenia

Proszę O Obliczenia class=

Odpowiedź :

[tex]8\sqrt{3} = a\sqrt{3}[/tex]13. a

Z pitagorasa

[tex]10^{2} + 16^{2} = c^{2}[/tex]

100 + 256 =356

c =  [tex]\sqrt{356}[/tex]

b) [tex]15^{2} - 5^{2} = b^{2}[/tex]

225- 25 = 200

b = [tex]\sqrt{200}[/tex]

14.  [tex]24^{2} - 12^{2} = a^{2}[/tex]

576- 144 = 432

a = [tex]\sqrt{432}[/tex]

P = 12· [tex]\sqrt{434}[/tex] ·[tex]\frac{1}{2}[/tex] = [tex]6\sqrt{432}[/tex]

Obw = 12+ 24 + [tex]\sqrt{432}[/tex] = 36 + [tex]\sqrt{432}[/tex]

15. h = [tex]4\sqrt{3}[/tex]

h = [tex]\frac{a\sqrt{3} }{2}[/tex]

[tex]4\sqrt{3}[/tex] = [tex]\frac{a\sqrt{3} }{2}[/tex] / 2

8 = a

Obw = 8*3 = 24

P = [tex]\frac{a^{2}\sqrt{3} }{4}[/tex]

P = [tex]16\sqrt{3}[/tex]