Wzory :
[tex]\Delta=b^2-4ac\\\\p=\frac{-b}{2a}\\\\q=\frac{-\Delta}{4a}[/tex]
1]
[tex]y=6x^2+3x-1\\\\a=6, \ b=3, \ c=-1\\\\\Delta=3^2-4\cdot6\cdot(-1)=9+24=33\\\\p=\frac{-3}{2\cdot6}=-\frac{3}{12}=-\frac{1}{4}\\\\q=-\frac{33}{4\cdot6}=-\frac{33}{24}=-\frac{11}{8}[/tex]
2]
[tex]y=-2x^2+4x+2\\\\a=-2, \ b=4, \ c=2\\\\\Delta=4^2-4\cdot(-2)\cdot2=16+16=32\\\\p=\frac{-4}{2\cdot(-2)}=\frac{-4}{-4}=1\\\\q=\frac{-32}{4\cdot(-2)}=\frac{-32}{-8}=4[/tex]
3]
[tex]y=x^2+15x-6\\\\a=1, \ b=15, \ c=-6\\\\\Delta=15^2-4\cdot1\cdot(-6)=225+24=249\\\\p=\frac{-15}{2}=-7,5\\\\q=\frac{-249}{4}=-62,25[/tex]
4]
[tex]y=2x^2+8x+16\\\\a=2, \ b=8, \ c=16\\\\\Delta=8^2-4\cdot2\cdot16=64-128=-64\\\\p=\frac{-8}{2\cdot2}=\frac{-8}{4}=-2\\\\q=\frac{-(-64)}{4\cdot2}=\frac{64}{8}=8[/tex]
5]
[tex]y=x^2-10x-7\\\\a=1, b=-10, \ c=-7\\\\\Delta=(-10)^2-4\cdot1\cdot(-7)=100+28=128\\\\p=\frac{-(-10)}{2\cdot1}=\frac{10}{2}=5\\\\q=\frac{-128}{4\cdot1}=-\frac{128}{4}=32[/tex]
