zadanie w załączniku​

Zadanie W Załączniku class=

Odpowiedź :

[tex]\sqrt{10}\cdot\sqrt{12,1}=\sqrt{10\cdot12,1}=\sqrt{121}=11\\\\\sqrt7\cdot\sqrt{28}=\sqrt{7\cdot28}=\sqrt{196}=14\\\\\sqrt2\cdot\sqrt{32}=\sqrt{2\cdot32}=\sqrt{64}=8\\\\\sqrt{50}\cdot\sqrt{\frac{1}{2}}=\sqrt{50\cdot\frac{1}{2}}=\sqrt{25}=5\\\\\sqrt{8}\cdot\sqrt{32}=\sqrt{8\cdot32}=\sqrt{256}=16\\\\\sqrt{20}\cdot\sqrt{10}\cdot\sqrt2=\sqrt{20\cdot10\cdot2}=\sqrt{400}=20\\\\\sqrt{18}:{\sqrt2}=\sqrt{18:2}=\sqrt9=3\\\\\sqrt{56}:\sqrt{3,5}=\sqrt{56:3,5}=\sqrt{16}=4\\\\\sqrt{125}:\sqrt5=\sqrt{125:5}=\sqrt{25}=5[/tex]

[tex]\sqrt{0,03}:\sqrt3=\sqrt{0,03:3}=\sqrt{0,01}=0,1[/tex]