[tex]\sqrt{31}>\sqrt{25}=5\\\sqrt{47}<\sqrt{49}=7\\\sqrt{99}>\sqrt{81}=9\\ \sqrt{90}>\sqrt{81}=9\\ \sqrt[3]{70}<\sqrt[3]{125}=5\\ \sqrt[3]{-10}<\sqrt[3]{-1}=-1\\ 2\sqrt{67}=\sqrt{268}>\sqrt{256}=16\\ \frac{1}{3} \sqrt{35}=\sqrt{\frac{35}{9} }=\sqrt{3\frac{8}{9} } <\sqrt{4} =2\\ \frac{2\sqrt{80} }{3} =\sqrt{\frac{320}{9} } =\sqrt{35\frac{5}{9} } <\sqrt{36}=6[/tex]
