[tex]dane:\\m = 1,25 \ t = 1 \ 250 \ kg\\v = 7,5\frac{m}{s}\\g = 10\frac{m}{s^{2}}\\szukane:\\h = ?\\\\Rozwiazanie\\\\Z \ zasady \ zachowania energii \ mechanicznej\\\\E_{p} = E_{k}\\\\mgh = \frac{mv^{2}}{2} \ \ /:mg\\\\h = \frac{v^{2}}{2g}\\\\h = \frac{(7,5\frac{m}{s})^{2}}{2\cdot10\frac{m}{s^{2}}} = \frac{56,25\frac{m^{2}}{s^{2}}}{20\frac{m}{s^{2}}}\\\\h \approx2,8 \ m[/tex]
