Odpowiedź: 1. 2,3% 2. 52,4%
1.
dane:
mH20 =1l=1000g
ms= 30g
mr = ms +mH2O
mr= 30g + 1000g=1300g
C%= ms/mr *100%
C%=30g/1300g*100%
C% = 2,3%
2.
Rozpuszczalność KNO3 W temp. 60st,Cwynosi: 110g /100g wody
ms =110g
mr =ms + mH2O =110g +100g=210g
C%=ms/mr *100%
C% =110g/210g*100%
C%=52,4%