[tex]2 \sqrt{6}x - 3 {x}^{2} - 2 < 0[/tex]
[tex] - 3 {x}^{2} + 2 \sqrt{6}x - 2 < 0[/tex]
∆=
[tex] {b}^{2} - 4ac = {(2 \sqrt{6}) }^{2} - 4 \times ( - 3) \times ( - 2) = 24 - 24 = 0[/tex]
[tex] x_{0} = \frac{ - b}{2a} = \frac{ - 2 \sqrt{6} }{2 \times ( - 3)} = \frac{ - 2 \sqrt{6} }{ - 6} = \frac{1}{3} \sqrt{6} [/tex]
