Odpowiedź:
[tex]log_{a}b = c\\a^{c} = b\\[/tex]
[tex]a) \\ log_{2}4 = 2\\\\\\b)\\ log_{\sqrt{3} }27 =6\\\\c)\\log_{2}8\sqrt{8} = \frac{9}{2} = 4,5[/tex]
[tex]a) \ log_{2}4 = log_{2}2^{2} = 2\\\\b) \ log_{\sqrt{3}}27 = log_{\sqrt{3}}(\sqrt{3})^{6} = 6\\\\c) \ log_{2}8\sqrt{8}=log_{2}2^{3}\sqrt{2^{3}} = log_{2}(2^{3}\cdot2\cdot2^{\frac{1}{2}}) = log_{2}2^{4,5} =4,5[/tex]
