Zadanie 2.
a)
x - (2x - 1) - 2x = 2(3x - 4)
-x - 2x + 1 = 6x - 8 l -1
-3x = 6x - 9 l -6x
-9x = -9 l :(-9)
x = 1
[tex]b)\\\\\frac{x+1}{2}+x=\frac{x+2}{3}\ \ \ \mid\cdot6\\\\3(x+1)+6x= 2(x+2)\\\\ 3x+3+6x= 2x+4 \ \ \ \mid-3\\\\9x=2x+1\ \ \ \mid-2x\\\\7x=1\ \ \ \mid:7\\\\x=\frac{1}{7}[/tex]
