Odpowiedź :
[tex]a) \ 4(3x+5)+7(5y-2) = 12x+20+35y-14 = 12x+35y+6\\\\b) \ 3x(4x-3)+x(2x-5) = 12x^{2}-9x+2x^{2}-5x = 14x^{2}-14x\\\\c) \ 2x(3x-4)-6x(x-1) = 6x^{2}-8x-6x^{2}+6x = -2x[/tex]
[tex]a) \ 4(3x+5)+7(5y-2) = 12x+20+35y-14 = 12x+35y+6\\\\b) \ 3x(4x-3)+x(2x-5) = 12x^{2}-9x+2x^{2}-5x = 14x^{2}-14x\\\\c) \ 2x(3x-4)-6x(x-1) = 6x^{2}-8x-6x^{2}+6x = -2x[/tex]