Odpowiedź :
[tex]Zadanie\\\\H=16\ dm\\V=256\ dm^{3}\\\\V=\frac{1}{3}\cdot P_{p}\cdot H\\\\\frac{1}{3} \cdot P_{p}\cdot 16=256\ \ \mid:16\\\\\frac{1}{3} \cdot P_{p}=16\ \ \mid\cdot 3\\\\ P_{p}=48\ dm^{2}[/tex]
[tex]Zadanie\\\\H=16\ dm\\V=256\ dm^{3}\\\\V=\frac{1}{3}\cdot P_{p}\cdot H\\\\\frac{1}{3} \cdot P_{p}\cdot 16=256\ \ \mid:16\\\\\frac{1}{3} \cdot P_{p}=16\ \ \mid\cdot 3\\\\ P_{p}=48\ dm^{2}[/tex]