Odpowiedź:
[tex]dla\ \ x=-1\\\\\frac{3x^2-x}{4}+3=\frac{3*(-1)^2-(-1)}{4}+3=\frac{3*1+1}{4}+3=\frac{3+1}{4}+3=\frac{4}{4}+3=1+3=4\\\\\\dla\ \ x=0\\\\\frac{3x^2-x}{4}+3=\frac{3*0^2-0}{4}+3=\frac{0}{4}+3=0+3=3\\\\\\dla\ \ x=1\\\\\frac{3x^2-x}{4}+3=\frac{3*1^2-1}{4}+3=\frac{3*1-1}{4}+3=\frac{3-1}{4}+3=\frac{2}{4}+3=\frac{1}{2}+3=3\frac{1}{2}[/tex]
