Odpowiedź:
[tex]c)\\\\\frac{x-3}{4}+1=\frac{1}{4}-3x\ \ /*4\\\\x-3+4=1-12x\\\\x+1=1-12x\\\\x+12x=1-1\\\\13x=0\ \ /:13\\\\x=0[/tex]
[tex]d)\\\\\frac{1}{5}-0,2x=\frac{2}{5}x-2(x+3)\\\\\frac{1}{5}-\frac{1}{5}x=\frac{2}{5}x-2x-6\ \ /*5\\\\1-x=2x-10x-30\\\\1-x=-8x-30\\\\-x+8x=-30-1\\\\7x=-31\ \ /:7\\\\x=-\frac{31}{7}\\\\x=-4\frac{3}{7}[/tex]
[tex]Zad\ \ 7\\\\c)\\\\\frac{2x-1}{2}-\frac{3x-1}{3}=1+\frac{x-1}{4}\ \ /*12\\\\6(2x-1)-4(3x-1)=12+3(x-1)\\\\12x-6-12x+4=12+3x-3\\\\-2=9+3x\\\\-3x=9+2\\\\-3x=11\ \ /:(-3)\\\\x=-\frac{11}{3}\\\\x=-3\frac{2}{3}[/tex]
