Odpowiedź:
Szczegółowe wyjaśnienie:
[tex]\left \{ {{0,2y=\frac{6x+y}{5}+1 |*5} \atop {x-1=\frac{y-5}{6}}|*6} \right. \\\left \{ {{y=6x+y+5} \atop {6x-6=y-5}} \right. \\\left \{ {{x=\frac{-5}{6} } \atop {6*\frac{-5}{6}-6+5 =y}} \right. \\\left \{ {{x=-\frac{5}{6} } \atop {y=-6}} \right.[/tex]
