Odpowiedź:a)2700(kg/m3)÷1000=2,7g/ cm3
B)8,44 g/cm3 x1000= 8440 kg/m3
C)0,8 g/cm3 ×1000= 800÷10=80 dag/dm3
2. 0,9(g/cm3)×5=4,5 g/cm3
Wyjaśnienie:
1.
[tex]a) \ 2700\frac{kg}{m^{3}} = 2700\cdot\frac{1000 \ g}{1000000 \ cm^{3}} = 2700\cdot\frac{1}{1000} \ \frac{g}{cm^{3}} = 2,7\frac{g}{cm^{3}}\\\\b) \ 8,44\frac{g}{cm^{3}} = 8,44\cdot\frac{0,001 \ kg}{0,000001 \ m^{3}} = 8,44\cdot1000 \ \frac{kg}{m^{3}} = 8440\frac{kg}{m^{3}}\\\\c) \ 0,8\frac{g}{cm^{3}} = 0,8\cdot\frac{0,1 \ dag}{0,001 \ dm^{3}} = 0,8 \cdot100 \ \frac{dag}{dm^{3}} = 80\frac{dag}{dm^{3}}[/tex]
2.
[tex]dane:\\V = 5 \ l = 5\cdot1000 \ cm^{3}} = 5 \ 000 \ cm^{3}\\d = 0,9\frac{g}{cm^{3}}\\szukane:\\m = ?\\\\Rozwiazanie\\\\d = \frac{m}{V} \ \ /\cdot V\\\\m = V\cdot d\\\\m = 5000 \ cm^{3}\cdot0,9\frac{g}{cm^{3}} = 4 \ 500 \ g = 4,5 \ kg[/tex]
