1.
[tex]a) \ h = \frac{a\sqrt{3}}{2} = \frac{6\sqrt{3}}{2} = 3\sqrt{3} \ cm \ \ \ \ PRAWDA\\\\b) \ d = a\sqrt{2} = 8\sqrt{2} \ cm \neq 4\sqrt{2} \ cm \ \ \ \ FALSZ\\\\c) \ P = \frac{a^{2}}{4} = \fracP12^{2}\cdot\sqrt{3}}{4} = =\frac{144\sqrt{3}}{4} = 36\sqrt{3} \ \ \ \ PRAWDA\\\\d) \ d=\sqrt{12^{2}+9^{2}}} = \sqrt{144+81} =\sqrt{225} = 15 \ \ \ \ PRAWDA[/tex]
