Odpowiedź:
[tex]a)\ \ 1\frac{3}{5}-2\frac{1}{6}=\frac{8}{5}-\frac{13}{6}=\frac{48}{30}-\frac{65}{30}=-\frac{17}{30}\\\\b)\ \ 3\frac{3}{8}+2\frac{5}{6}=3\frac{9}{24}+2\frac{20}{24}=5\frac{29}{24}=6\frac{5}{24}\\\\c)\ \ \frac{1}{2}-(-\frac{1}{6}-\frac{1}{3})=\frac{1}{2}-(-\frac{1}{6}-\frac{2}{6})=\frac{1}{2}-(-\frac{3}{6})=\frac{1}{2}+\frac{3}{6}=\frac{1}{2}+\frac{1}{2}=1[/tex]
[tex]d)\ \ \frac{7}{6}+(-\frac{5}{4}-\frac{4}{3})=\frac{7}{6}+(-\frac{15}{12}-\frac{16}{12})=\frac{7}{6}+(-\frac{31}{12})=\frac{7}{6}-\frac{31}{12}=\frac{14}{12}-\frac{31}{12}=-\frac{17}{12}=-1\frac{5}{12}\\\\e)\ \ -(-2\frac{2}{3})+\frac{7}{15}=2\frac{2}{3}+\frac{7}{15}=2\frac{10}{15}+\frac{7}{15}=2\frac{17}{15}=3\frac{2}{15}[/tex]
[tex]f)\ \ -1\frac{9}{16}+\frac{11}{12}=-\frac{25}{16}+\frac{11}{12}=-\frac{75}{48}+\frac{44}{48}=-\frac{31}{48}[/tex]
