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Poproszę pełne działania

Poproszę Pełne Działania class=

Odpowiedź :

Odpowiedź:

2/3 + 1/5 = 10/15 + 3/15 = 13/15

5/6 - 3/4 = 10/12 - 9/12 = 1/12

7/20 - 1/4 = 7/20 - 5/20 = 2/20 = 1/10

5 i 1/4 - 2 i 1/6 = 5 i 3/12 - 2 i 2/12 = 3 i 1/12

4 i 1/3 + 2 i 1/6 = 4 i 2/6 + 2 i 1/6 = 6 i 3/6 = 6 i 1/2

4 i 1/2 - 1 i 3/4 = 4 i 2/4 - 1 i 3/4 = 3 i 6/4 - 1 i 3/4 = 2 i 3/4

1 i 3/4 - 1/3 = 1 i 9/12 - 4/12 = 1 i 5/12  ---- tyle soku zostało w dzbanie

Peter9996viz

Odpowiedź:

[tex] \frac{2}{3} + \frac{1}{5} = \frac{10}{15} + \frac{3}{15} = \frac{13}{15} [/tex]

[tex] \frac{5}{6} - \frac{3}{4} = \frac{10}{12} - \frac{9}{12} = \frac{1}{12} [/tex]

[tex] \frac{7}{20} - \frac{1}{4} = \frac{7}{20} - \frac{5}{20} = \frac{2}{20} = \frac{1}{10} [/tex]

[tex]5 \frac{1}{4} - 2 \frac{1}{6} = \frac{21}{4} - \frac{13}{6} = \frac{63}{12} - \frac{26}{12} = \frac{37}{12} = \\ 3 \frac{1}{12} [/tex]

[tex]4 \frac{1}{3} + 2 \frac{1}{6} = \frac{13}{3} + \frac{13}{6} = \frac{26}{6} + \frac{13}{6} = \frac{39}{6} = \\ \frac{13}{2} = 6 \frac{1}{2} [/tex]

[tex]4 \frac{1}{2} - 1 \frac{3}{4} = \frac{9}{2} - \frac{7}{4} = \frac{18}{4} - \frac{7}{4} = \frac{11}{4} = 2 \frac{3}{4} [/tex]

[tex]1 \frac{3}{4} - \frac{1}{3} = \frac{7}{4} - \frac{1}{3} = \frac{21}{12} - \frac{4}{12} = \frac{17}{12} = 1 \frac{5}{12} [/tex]

W dzbanku zostało 1 i 5/12 litra soku.

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