Odpowiedź :
Odpowiedź:
[tex] \sqrt{1 \frac{17}{64} } \times \sqrt{1 \frac{7}{9} } - ( \sqrt{6 \frac{1}{4} } - \sqrt{2 \frac{7}{9} } ) \div \sqrt{1 \frac{9}{16} } = \sqrt{ \frac{81}{64} } \times \sqrt{ \frac{16}{9} } - ( \sqrt{ \frac{25}{4} } - \sqrt{ \frac{25}{9} } ) \div \sqrt{ \frac{25}{16} } = \frac{9}{8} \times \frac{4}{3} - ( \frac{5}{2} - \frac{5}{3} ) \div \frac{5}{4} = \frac{3}{2} - ( \frac{15}{6} - \frac{10}{6} ) \times \frac{4}{5} = \frac{3}{2} - \frac{5}{6} \times \frac{4}{5} = \frac{3}{2} - \frac{2}{3} = 1 \frac{1}{2} - \frac{2}{3} = 1 \frac{3}{6} - \frac{4}{6} = \frac{5}{6} [/tex]