c)
[tex]\begin{cases} \frac{1}{2}x +\frac{1}{3}y = 1 \ \ \ |\cdot 6 \\ - 2x + y = -4 \ \ \ |\cdot (-2) \end{cases} \\\\ \underline{\begin{cases} 3x +2y =6 \\ 4x-2y = 8\end{cases}} \ \ \ |+ \\\\ 7x = 14 \ \ \ |:7 \\ x = 2 \\\\ - 2x + y = -4 \\ - 2 \cdot 2 + y = - 4 \\ - 4 + y = -4 \\ y = -4+4 \\ y = 0 \\\\ \begin{cases} x = 2 \\ y = 0 \end{cases}[/tex]
Odp. x = 2 i y = 0.
