[tex]\frac{(-\frac{2}{3})(2-6\cdot1\frac{}{3})}{3\frac{3}{5}+1,2:\frac{3}{5}} = \frac{(-\frac{2}{3})(2-6\cdot\frac{4}{3})}{3,6+1,2:0,6}=\frac{-\frac{2}{3}(2-8)}{3,6+2}=\frac{-\frac{2}{3}\cdot(-6)}{5,6} =\frac{4}{5,6} = \frac{40}{56} = \frac{5}{7}[/tex]
