Odpowiedź :
M(Ca(OH)2)=40g/mol+2*16g/mol+2*1g/mol=74g/mol
1mol Ca ---------------74g Ca(OH)2
xmol Ca --------------100g Ca(OH)2
x=1mol*100g/74g
x=1,4mol
2mol O ---------------74g Ca(OH)2
xmol O --------------100g Ca(OH)2
x=2mol*100g/74g
x=2,7mol
[tex]M_C_a_(_O_H_)_2= 74g/mol [/tex]
Obliczam liczbę moli wapnia:
1mol Ca--> 74g Ca(OH)₂
x --> 100g Ca(OH)₂
x= 1,35mol
Obliczam liczbę moli tlenu
2mol O--> 74g Ca(OH)₂
x --> 100g Ca(OH)₂
x= 2,7 mol