Odpowiedź :
W(x)= x3- 3x2-2x+6
x³-3x²-2x+6= x²(x-3)-2(x-3)= (x-3)(x²-2)
W(x)=(x-3)(x²-2)
(;
x³-3x²-2x+6= x²(x-3)-2(x-3)= (x-3)(x²-2)
W(x)=(x-3)(x²-2)
(;
W(x)= x³- 3x²-2x+6 = x(x²-2)-3(x²-2) = (x-3)(x²-2) = (x-3)(x-√2)(x+√2)