[tex]\\\frac{x^2-7x+12}{x^2-4x+3}>0 \\\frac{x^2-3x-4x+12}{x^2-x-3x+3}>0 \\\frac{x(x-3)-4(x-3)}{x(x-1)-3(x-1)}>0 \\\frac{(x-3)(x-4)}{(x-1)(x-3)}>0, \ \ zal. \ x\in R\backslash\{1,3\} \\\frac{x-4}{x-1}>0 /*(x-1)^2 \\(x-1)(x-4)>0 \\m.z. \ x_1=1, \ x_2=4, \ a>0 \\x\in(-\infty,1)\cup(4,\+\infty)[/tex]
