Rozwiązane

Rozwiąż:
(x^2 - 1/x^2)^5=

Gdzie ^2 i ^5 to potęgi

Odpowiedź :

(x² - 1/x²)⁵=1(x²)⁵-5(x²)⁴(1/x²)+10(x²)³(1/x²)²-10(x²)²(1/x²)³+5(x²)(1/x²)⁴-(1/x²)⁵=x¹⁰-5x⁸(1/x²)+10x⁶(1/x⁴)-10x⁴(1/x⁶)+5x²(1/x⁸)-(1/x¹⁰
=x¹⁰-5x⁶+10x²-10(1/x²)+5(1/x⁶)-(1/x¹⁰)

Gdzie ^2 i ^5 to potęgi

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