[tex]Dane:\\ T=1s\\ g=10\frac{m}{s^2}\\ Oblicz:\\ l=?\\ Rozwiazanie:\\ T=2\pi\sqrt{\frac{l}{g}}\Rightarrow l=\frac{gT^2}{2^2*\pi^2}\\\\ l=\frac{10^2*1}{4*3,14^2}\\\\ l=\frac{100}{4*9,8596}\\\\ l=\frac{100}{39,4384}\\\\ l=2,5m[/tex]
