Odpowiedź:
[tex]a) y=\frac{1}{2}*4=2\\z=\frac{1}{2}*4\sqrt{2}=2\sqrt{2} \\y=z=2\sqrt{2} \\\\b) (\frac{1}{2}*4\sqrt{2})^2+H^2=6^2\\(2\sqrt{2})^2+H^2=36\\4*2+H^2=36\\8+H^2=36\\H^2=28 /\sqrt{x} \\H=2\sqrt{7} \\\\c)(\frac{1}{2}*12\sqrt{2})^2+5^2=x^2\\(6\sqrt{2})^2+25=x^2\\36*2+25=x^2\\72+25=x^2\\97=x^2 /\sqrt{x} \\x=\sqrt{97}[/tex]
