[tex]-\frac{1}{6}+3=-\frac{1}{6}+\frac{3}{1}=-\frac{1}{6}+\frac{3\cdot6}{1\cdot6}=-\frac{1}{6}+\frac{18}{6}=\frac{17}{6}=2\frac{5}{6}[/tex]
