Odpowiedź:
z.2
a) x² = 8² + 15² = 64 +225 = 289
x = [tex]\sqrt{289}[/tex] = 13
b) y² + (√3)² = (√7)²
y² = 7 - 3 = 4
y = √4 = 2
z.3
a √2 = √2 ⇒ a = 1
L = 4 a = 4*1 = 4
z.4
x² + (√5)² = 3²
x² = 9 - 5 = 4
x = √4 = 2
L = 3 + 2 + √5 = 5 + √5
z.5
Boki o długościach:
a) 10,10, 8
h² + 4² = 10²
h² = 100 - 16 = 84 = 4*21
h = √84 = 2 √21
P = 0,5*8*2√21 = 8[tex]\sqrt{21}[/tex] =
b) 8, 8, 10
h² +5² = 8²2
h² = 64 - 25 = 39
h = [tex]\sqrt{39}[/tex]
P = 0,5*10*[tex]\sqrt{39}[/tex] = 5 [tex]\sqrt{39}[/tex] =
Dokończ.
Szczegółowe wyjaśnienie:
