[tex]Dane:\\v_{o} = 0\\m = 400 \ g = 0,4 \ kg\\h = 0,8 \ m \\g = 10\frac{N}{kg}\\Szukane:\\E_{k} = ?\\\\Rozwiazanie\\\\Z \ zasady \ zachowania \ energii\\\\E_{p} = E_{k}\\\\mgh = E_{k}\\\\E_{k} = mgh\\\\E_{k} = 0,4 \ kg\cdot10\frac{N}{kg}\cdot0,8 \ m\\\\\boxed{E_{k} = 3,2 \ J}[/tex]
Odp. Energia kinetyczna doniczki Ek = 3,2 J (dżula).
