Odpowiedź:
[tex]\begin{cases}\frac{x-2}{3}+y=1\ \ /\cdot3\\\frac{x-2}{6}+2y=-1\ \ /\cdot6\end{cases}\\\\\\\begin{cases}x-2+3y=3\\x-2+12y=-6\end{cases}\\\\\\\begin{cases}x+3y=3+2\\x+12y=-6+2\end{cases}\\\\\\\begin{cases}x+3y=5\ \ /\cdot(-1)\\x+12y=-4\end{cases}\\\\\\+\begin{cases}-x-3y=-5\\x+12y=-4\end{cases}\\--------\\9y=-9\ \ /:9\\y=-1\\\\\\x+3\cdot(-1)=5\\\\x-3=5\\\\x=5+3\\\\x=8\\\\\\\begin{cases}x=8\\y=-1\end{cases}[/tex]
