Odpowiedź:
zad.12
[tex]16 = {2}^{4} \\ 25 = {5}^{2} \\ 27 = {3}^{3} \\ 32 = {2}^{5} \\ 64 = {2}^{6} \\ 81 = {3}^{4} \\ 125 = {5}^{3} \\ 128 = {2}^{7} [/tex]
zad.13
[tex]{8}^{2} \div {4}^{2} = (8 \div 4 {)}^{2} = {2}^{2} \\ {4}^{3} \times 16= {2}^{2 ^{3} } \times {2}^{4} = {2}^{10} \\ 4^{3 ^{2} } = {2}^{2^{3 ^{2} } } = {2}^{12} \\ {64}^{2} = {2}^{6 ^{2} } = {2}^{12} [/tex]
