Odpowiedź :
[tex]64mm = 6.4cm \\ 48mm = 4.8cm[/tex]
Z tw. Pitagorasa obliczmy bok rombu
[tex] {3.2}^{2} + {2.4}^{2} = {x}^{2} \\ 10.24 + 5.76 = {x}^{2} \\ {x}^{2} = 16 \\ x = \sqrt{16} \\ x = 4cm[/tex]
Obwód
[tex]4 \times 4cm = \underline{16cm}[/tex]