Odpowiedź:
[tex]d = a\sqrt{2} \\10 = a \sqrt{2} / :\sqrt{2} \\\frac{10 * \sqrt{2} }{\sqrt{2} * \sqrt{2} } = a\\\\a = \frac{10\sqrt{2} }{2} \\a = 5\sqrt{2} \\\\Ob = 4a\\Ob = 20\sqrt{2} \\\\Pole = a^{2} \\Pole = (5\sqrt{2}) ^{2} \\Pole = 25 * 2 \\Pole = 50[/tex]
Odp : BD
