Odpowiedź:
[tex]v = 32 \\ h = 4 \\ \\ v = p \frac{}{p} \times h \\ 32 = {a}^{2} \times 4 \\ {a}^{2} = 8 \\ a = 2 \sqrt{2} [/tex]
[tex]d = a \sqrt{2} = 2 \sqrt{2} \times \sqrt{2} = 4[/tex]
[tex] {h}^{2} + {( \frac{1}{2}d) }^{2} = {b}^{2} \\ {4}^{2} + {2}^{2} = {b}^{2} \\ {b}^{2} = 20 \\ b = 2 \sqrt{5} [/tex]
