Odpowiedź:
1) [tex]\log 1000 = \log (10^3) = 3[/tex]
2) [tex]\log_{3}9\sqrt{2} - \log_{3}2\sqrt{2} + \log_{3}2 = \log_{3}\frac{9\sqrt{2}}{2\sqrt{2}} + \log_{3}2 = \log_{3}(\frac{9\sqrt{2}}{2\sqrt{2}} \cdot 2) = \log_3{9} = \log_3{(3^2)} = 2[/tex]
3) [tex]3\log_{7}49 = 3\log_{7}(7^2) = 3\cdot 2 = 6[/tex]