a)
[tex]2t - (3t + 1) = 6 \\ 2t - 3t - 1 = 6 | + 1 \\ - t = 7 | \times ( - 1) \\ t = - 7[/tex]
b)
[tex]x - 7 - 2(3x + 5) = 3 \\ x - 7 - 6x - 10 = 3 | + 17 \\ - 5x = 20 | \times ( - 1) \\ 5x = - 20 | \div 5 \\ x = - 4[/tex]
c)
[tex] - (4 + x) = 2(3 - x) \\ - 4 - x = 6 - 2x | + 4 \\ - x = 10 - 2x | + 2x \\ x = 10[/tex]
Odpowiedź:
A)
2t-(3t+1)=6
2t - 3t - 1 = 6
-t = 7
t = - 7
B)
x-7-2(3x+5)=3
x - 7 - 6x - 10 = 3
- 5x = 20
x = - 4
C)
-(4+x)=2(3-x)
- 4 - x = 6 - 2x
x = 10
