Odpowiedź :
a) [tex]6\sqrt{7} + 2(3-2\sqrt{7}) = 6\sqrt{7} + 6 - 4\sqrt{7} = 2\sqrt{7} + 6[/tex]
b) [tex]3 - 2\sqrt{5} - (4\sqrt{5} - 6) = 3 - 2\sqrt{5} - 4\sqrt{5} + 6 = 9 - 6\sqrt{5}[/tex]
c) [tex]-3\sqrt{6} - 3(1-2\sqrt{6}) = -3\sqrt{6} - 3 + 6\sqrt{6} = 3\sqrt{6} -3[/tex]
d) [tex]5(2+4\sqrt{3}) + 2(\sqrt{3}-5) = 10 + 20\sqrt{3} + 2\sqrt{3} - 10 = 22\sqrt{3}[/tex]
e) [tex]3(2\sqrt[3]{2} ) - (5\sqrt[3]{2} + 4) = 6\sqrt[3]{2} - 5\sqrt[3]{2} - 4 = \sqrt[3]{2} - 4[/tex]
f) [tex]-2(5\sqrt[3]{7} ) - 3(2\sqrt[3]{7} + 3) = -10\sqrt[3]{7} - 6\sqrt[3]{7} - 9 = -16\sqrt[3]{7} - 9[/tex]