Odpowiedź:
Ur=120V
Ir=10A
Us=160V
Is=3,2A
E=U+I*Rw
E=120+10*Rw
E=160+3,2*Rw
120+10*Rw=160+3,2*Rw
6,8*Rw=40
Rw=5,88Ω
E=120V+10A*5,88Ω
E=178,8V
R=U/I
Rr=120V/10A
Rr=12Ω
Rs=160V/3,2A
Rs=50Ω
Rr=R1*R2/(R1+R2)
Rs=R1+R2
12=R1*R2/(R1+R2)
50=R1+R2 → R1=50-R2
12*(50-R2+R2)=(50-R2)*R2
600=50R2-R2²
R²-50R+600=0
Δ=2500-4*600
Δ=100
√Δ=10
R1=(50-10)/2
R1=20Ω
R2=(50+10)/2
R2=30Ω
