Odpowiedź :
[tex]\frac34+\frac2{14}=\frac{21}{28}+\frac{4}{28}=\frac{25}{28}\\\\\frac34+\frac23=\frac{9}{12}+\frac{8}{12}=\frac{17}{12}=1\frac5{12}\\\\\frac38+\frac56=\frac{9}{24}+\frac{20}{24}=\frac{29}{24}=1\frac5{24}\\\\11\frac79+8\frac5{12}=11\frac{28}{36}+8\frac{15}{36}=19\frac{43}{36}=20\frac7{36}\\\\1\frac13+8\frac5{12}=1\frac{4}{12}+8\frac5{12}=9\frac9{12}=9\frac34\\\\1\frac13+4\frac34+\frac1{12}=1\frac{4}{12}+4\frac{9}{12}+\frac1{12}=5\frac{14}{12}=6\frac2{12}=6\frac16\\\\[/tex]
[tex]\frac56-\frac5{12}=\frac{10}{12}-\frac5{12}=\frac5{12}\\\\\frac35-\frac13=\frac{9}{15}-\frac{5}{15}=\frac4{15}\\\\\frac89-\frac56=\frac{16}{18}-\frac{15}{18}=\frac1{18}\\\\2\frac23-\frac14=2\frac{8}{12}-\frac{3}{12}=2\frac5{12}\\\\4\frac37-\frac12=4\frac{6}{14}-\frac7{14}=3\frac{20}{14}-\frac7{14}=3\frac{13}{14}\\\\12\frac59-7\frac{13}{15}=12\frac{25}{45}-7\frac{39}{45}=11\frac{70}{45}-7\frac{39}{45}=4\frac{31}{45}[/tex]